www.1862.net > ( )除16=4/1=3:( )=( )%要求填空

( )除16=4/1=3:( )=( )%要求填空

15/16+(7/16-1/4)÷3/4 =15/16+(7/16-4/16)x4/3 =15/16+3/16x4/3 =15/16+4/16 =19/16

15/8X[4/3÷(16/3-4/1)] =15/8X[4/3÷(-16/1)] =15/8X(-4/3) =-5/2

3/16÷[1一(3/4一3/8)] =3/16÷(1-3/8) =3/16÷5/8 =3/16x8/5 =3/10

-4?3/4?1??5 =-4x4/3+5 =5-16/3 =-1/3

解: [3/4-(7/16-1/4)]/9/32 =[3/4-3/16]/9/32 =9/16/9/32 =9/16X32/9 =2

16/9

不正确。因为括号外为除法,所以括号内应该变号,将除号变为乘号。所以应变为3除以1/16即48

(1)13+3=16,32×2=64.数列为:1,2,4,4,7,8,10,16,13,32,16,64,19,128.(2)8-5=3,13=8=5,13+3+5=21.故数列为:1,2,3,3,6,5,8,15,13,21,21,28,34.故答案为:16;64;21;21.

这道数学题无解。证明如下: 1+2+3+4+5+6+7+8=36, 设Q={1,2,3,4,5,6,7,8} 按顺序设括号内的数为a,b,c,d,e,f,g,h,a,b,c,d,e,f,g,h∈Q,a≠b≠c≠d≠e≠f≠g≠h 有(a-b)+(c+d)+(e-f)+(g+h)=1+9+2+7=19 即(a+b+c+d+e+f+g+h)-2b-2f=19 因为a+b+c+d+...

(1)根据规律从1开始的连续n个奇数的和:1+3+5+7+…+(2n-1)=n2,可得:2n-1=99,则n=50;所以1+3+5+7…+99=502=2500;(2)根据规律可得:20082-20072=2008×2-1=4015;a2-b2=(a+b)×(a-b),故答案为:50,2500;4015,a,b,a,b.

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